工作在放大区的某三极管,当IB从15μA增大到25μA时,IC从2mA增大到3mA,则其电流放大系数β约为()。
第1题:
有以下程序: Sub subP(b()As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4)As Integer a(i)=5 a(2)=6 a(3)=7 a(4)=8 subP a() For i=1 To 4 Print a(i) Next i End Sub 运行上面的程序,单击命令按钮,输出结果为______。
A. 2 4 6 8
B.5 6 7 8
C.10 12 14 6
D.出错
第2题:
有以下程序: Sub subP(b()As Integer) For i=1 To 4 b(i)=2*i Next i End Sub Private Sub Command1_Click() Dim a(1 To 4)As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 subPa() For i=1 To 4 Print a(i) Next i End Sub 运行上面的程序,单击命令按钮,输出结果为( )
A.2 4 6 8
B.5 6 7 8
C.10 12 14 16
D.出错
第3题:
有一过程如下:
Sub Sub1(m As Integer,total As Long)
Dim i As Integer
total=1
For i=1 To m
total=total*i
Next
End Sub
调用它的事件过程如下:
Private Sub Command1_Click()
Dim tot As Long,a As Integer
a=Val(InputBox("请输入数据"))
Call Sub1(a,tot)
Print tot
End Sub
则输入数据5,运行结果为【 】。
第4题:
下面程序的输出结果是【 】。
Private Sub Form_Click()
i=0
Do Until 0
i=i+1
if i>10 then Exit Do
Loop
Print i
End Sub
第5题:
A、Private Sub sele(ByVal A( ) As integer)
B、Private Function sale(A() As Integer) As String
C、Private Sub sale(A() As Integer) As Integer
D、Private Sub sale(A(i) As Integer)
第6题:
程序执行结果s的值是【 】.
Private Sub Command l-Click ()
I =0
Do
S= I +S
I = I + l
Loop Until I >=4
End Sub
第7题:
阅读程序: Sub p( b () As Integer)For i =1To 4 b(i) = 2(iNext i End Sub Private Sub Command1_Click()Dim a (1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 call p (a) For i=1 To 4 Print a(i) Next iEnd Sub运行上面的程序,单击命令按钮,输出结果为。
第8题:
设有如下通用过程: Public Sub Fun(a() As Integer, x As Integer) For i=1 To 5 x=x+a(i) Next End Sub 在窗体上画一个名称为Text1的文本框和一个名称为Command1的命令按钮。然后编写如下的事件过程: Private Sub Command1_Click() Dim arr(5)As Integer, n As Integer For i=1 To 5 art(i)=i+i Next Fun arr, n Text1. Text=Str(n) End Sub 程序运行后,单击命令按钮,在文本框中显示的内容是______。
A.30
B.25
C.20
D.15
第9题:
设有如下程序:
Private Sub Form. Click( )
Dim ary(1 To 5)As Integer
Dim i As Integer
Dim sum As Integer
For i=1 To 5
ary(i)=i+l
sum=sum+ary(i)
Next i
Print sum
End Sub
程序运行后,单击窗体,则在窗体上显示的是( )。
A.15
B.16
C.20
D.25
第10题:
以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }
A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4
B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18
C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4
D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18