工频正弦电流的Im=50A,初相φ=30°,它的数学解析式是i=()A。
第1题:
下面是用冒泡法将5个整数按升序排列,请将程序补充完整。
Sub GASR()
Dim m
m=Array(10, 1, 5, 6, 7)
For i=0 To 3
For j= 【13】
If m(i) >=m(j) Then
【14】
m(i) =m(j)
m(j) =t
End If
Next j
【15】
For i=0 To 4
Print m(i)
Next i
End Sub
第2题:
程序执行结果s的值是【 】.
Private Sub Command l-Click ()
I =0
Do
S= I +S
I = I + l
Loop Until I >=4
End Sub
第3题:
有一过程如下:
Sub Sub1(m As Integer,total As Long)
Dim i As Integer
total=1
For i=1 To m
total=total*i
Next
End Sub
调用它的事件过程如下:
Private Sub Command1_Click()
Dim tot As Long,a As Integer
a=Val(InputBox("请输入数据"))
Call Sub1(a,tot)
Print tot
End Sub
则输入数据5,运行结果为【 】。
第4题:
有如下程序: Private Sub Commandl_Click( ) Dim i As Integer For i=1 To 2 DS Next i End Sub Sub DS( ) Dim x As Integer,m As String Static y,n X=X + 1 y=y + 1 m=m &"*”:n=n&"#" Print x,y,m,n End Sub 程序运行后,输出的结果是
A.1 1 * #
B.1 1 * #
C.1 1 * # 1 1 * # 1 2 * #
D.1 1 * # 1 1 * ## 1 2 * ##
第5题:
A.i=sin50t
B.f=sin(314t+30°)
C.i=√2min(314t+30°)
D.i=√2sin(5Ot+30°)
第6题:
在窗体上画一个命令按钮,然后编写如下事件过程:
Sub BTC(oldCopy() As Integer, newCopy() As Integer)
Dim i As Integer
For i=LBound(oldCopy() ) To UBound(oldCopy() )
newCopy(i) =oldCopy(i)
Next i
End Sub
Private Sub Command1_Click()
Dim m(10) As Integer, n(10) As Integer
For i=1 To 10
m(i) =i i
Next i
Call BTC(m, n)
Print n(5)
End Sub
程序运行后,单击命令按钮输出结果为( )。
A.0
B.2
C.10
D.25
第7题:
阅读程序: Sub p( b () As Integer)For i =1To 4 b(i) = 2(iNext i End Sub Private Sub Command1_Click()Dim a (1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 call p (a) For i=1 To 4 Print a(i) Next iEnd Sub运行上面的程序,单击命令按钮,输出结果为。
第8题:
如果存在如下过程:
Private Function FMax(a() As Integer)
Dim First As Integer, Last As Integer, i As Integer
First=LBound(A)
Last=UBound(A)
Max=a(First)
For i=First To Last
If a(i) > Max Then Max=a(i)
Next i
FMax=Max
End Function
在窗体上添加一个命令按钮,然后编写如下事件过程:
Private Sub Command1_Click()
ReDim m(1 To 4) As Integer
m(1) =20: m(2) =30: m(3) =50: m(4) =100
c=FMax(m)
Print c
End Sub
单击命令按钮,其输出结果为 【12】 。
第9题:
A.50sin(314t+30°),390°,25A
B.50sin(314t+30°),360°,25A
C.50sin(314t+30°),390°,250A
第10题:
下面程序的输出结果是( )。 #include"stdio.h" int sub(int m) { static a=4; a+=m; return a; } void main() { int i=2,j=1,k; k=sub(i); k=sub(j); printf("%d",k); }
A.6
B.7
C.8
D.9