Oracle认证考试

Evaluate the following code：   SQL>VARIABLE task_name VARCHAR2（255）； SQL>VARIABLE sql_stmt VARCHAR2（4000）； SQL>BEGIN ：sql_stmt ：= ’SELECT COUNT（*） FROM customers  WHERE cust_state_province =’’CA’’’； ：task_name ：= ’MY_QUICKTUNE_TASK’；  DBMS_ADVISOR.QUICK_

题目

Evaluate the following code：   SQL>VARIABLE task_name VARCHAR2（255）； SQL>VARIABLE sql_stmt VARCHAR2（4000）； SQL>BEGIN ：sql_stmt ：= ’SELECT COUNT（*） FROM customers  WHERE cust_state_province =’’CA’’’； ：task_name ：= ’MY_QUICKTUNE_TASK’；  DBMS_ADVISOR.QUICK_TUNE（DBMS_ADVISOR.SQLACCESS_ADVISOR，  ：task_name， ：sql_stmt）；  END；   What is the outcome of this block of code？（）  

  • A、 It creates a task and workload， and executes the task.
  • B、 It creates a task and workload but does not execute the task.
  • C、 It produces an error because a template has not been created.
  • D、 It produces an error because the SQL Tuning Set has not been created.
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相似问题和答案

第1题：

Evaluatethefollowingcode：SQL>VARIABLEtask_nameVARCHAR2（255）；SQL>VARIABLEsql_stmtVARCHAR2（4000）；SQL>BEGIN：sql_stmt：=’SELECTCOUNT（*）FROMcustomersWHEREcust_state_province=’’CA’’’；：task_name：=’MY_QUICKTUNE_TASK’；DBMS_ADVISOR.QUICK_TUNE（DBMS_ADVISOR.SQLACCESS_ADVISOR，：task_name，：sql_stmt）；END；Whatistheoutcomeofthisblockofcode？（）

A.Itcreatesataskandworkload，andexecutesthetask.

B.Itcreatesataskandworkloadbutdoesnotexecutethetask.

C.Itproducesanerrorbecauseatemplatehasnotbeencreated.

D.ItproducesanerrorbecausetheSQLTuningSethasnotbeencreated.


参考答案：A

第2题：

“雇员”表包含以下列：姓氏VARCHAR2（25） 名字VARCHAR2（25） 电子邮件VARCHAR2（50）如果要编写以下SELECT语句来检索具有电子邮件地址的雇员的姓名。SELECT姓氏||’，’||名字"雇员姓名"FROM雇员；则应使用哪条WHERE子句来完成此条语句？（）

  • A、WHERE电子邮件=NULL；
  • B、WHERE电子邮件!=NULL；
  • C、WHERE电子邮件IS NULL；
  • D、WHERE电子邮件IS NOT NULL；

正确答案:D

第3题：

The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER (4) NOT NULLCUSTOMER_NAME VARCHAR2 (100) NOT NULLSTREET_ADDRESS VARCHAR2 (150)CITY_ADDRESS VARHCAR2 (50)STATE_ADDRESS VARCHAR2 (50)PROVINCE_ADDRESS VARCHAR2 (50)COUNTRY_ADDRESS VARCHAR2 (50)POSTAL_CODE VARCHAR2 (12)CUSTOMER_PHONE VARCHAR2 (20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is.Which expression finds the number of different countries represented in the CUSTOMERS table?（）

A. COUNT(UPPER(country_address))

B. COUNT(DIFF(UPPER(country_address)))

C. COUNT(UNIQUE(UPPER(country_address)))

D. COUNT DISTINTC UPPER(country_address)

E. COUNT(DISTINTC (UPPER(country_address)))


参考答案：E

第4题：

Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view? （）

  • A、SELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary < b.maxsal;
  • B、SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))
  • C、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);
  • D、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

正确答案:A

第5题：

You accepted the recommended SQL Profile by executing the following code：   DECLARE   sqlprofile_name varchar2（30）；  BEGIN   sqlprofile_name ：= DBMS_SQLTUNE.ACCEPT_SQL_PROFILE（  task_name => ’my_task’，   profile_name => ’my_profile’）；   END；   Which advisor will analyze this profile？（）  

  • A、 SQL Access Advisor
  • B、 Undo Advisor
  • C、 Segment Advisor
  • D、 SQL Tuning Advisor

正确答案:D

第6题：

The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER(4) NOT NULLCUSTOMER_NAME VARCHAR2(100) NOT NULLSTREET_ADDRESS VARCHAR2(150)CITY_ADDRESS VARCHAR2(50)STATE_ADDRESS VARCHAR2(50)PROVINCE_ADDRESS VARCHAR2(50)COUNTRY_ADDRESS VARCHAR2(50)POSTAL_CODE VARCHAR2(12)CUSTOMER_PHONE VARCHAR2(20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?（）

A.COUNT(UPPER(country_address))

B.COUNT(DIFF(UPPER(country_address)))

C.COUNT(UNIQUE(UPPER(country_address)))

D.COUNT DISTINCT UPPER(country_address)

E.COUNT(DISTINCT (UPPER(country_address)))


参考答案：E

第7题：

The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which two statements find the number of customers? （）

  • A、SELECT TOTAL(*) FROM customer;
  • B、SELECT COUNT(*) FROM customer;
  • C、SELECT TOTAL(customer_id) FROM customer;
  • D、SELECT COUNT(customer_id) FROM customer;
  • E、SELECT COUNT(customers) FROM customer;
  • F、SELECT TOTAL(customer_name) FROM customer;

正确答案:B,D

第8题：

You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns:CUST_ID NUMBER(4) NOT NULLCUST_NAME VARCHAR2(100) NOT NULLCUST_ADDRESS VARCHAR2(150)CUST_PHONE VARCHAR2(20)Which SELECT statement accomplishes this task?（）

A. SELECT* FROM customers;

B. SELECT name, address FROM customers;

C. SELECT id, name, address, phone FROM customers;

D. SELECT cust_name, cust_address FROM customers;

E. SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;


参考答案：D

第9题：

Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?（）

  • A、SELECT COUNT(*) FROM employees WHERE last_name='Smith';
  • B、SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';
  • C、SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';
  • D、SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';
  • E、SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';

正确答案:D

第10题：

Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid?（）

  • A、DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);
  • B、DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);
  • C、DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');
  • D、DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');

正确答案:C

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