1Z0-053

单选题Evaluate the following function code：   CREATE FUNCTION get_dept_avg（dept_id NUMBER） RETURN NUMBER RESULT_CACHE RELIES_ON （EMPLOYEES） IS avgsal NUMBER（6）； BEGIN  SELECT AVG（SALARY）INTO avgsal FROM EMPLOYEES   WHERE DEPARTMENT_ID = dept_id； RETURN avgsa

题目
单选题
Evaluate the following function code：   CREATE FUNCTION get_dept_avg（dept_id NUMBER） RETURN NUMBER RESULT_CACHE RELIES_ON （EMPLOYEES） IS avgsal NUMBER（6）； BEGIN  SELECT AVG（SALARY）INTO avgsal FROM EMPLOYEES   WHERE DEPARTMENT_ID = dept_id； RETURN avgsal； END get_dept_avg；   Which statement is true regarding the above function？（）
A

 The cached result becomes invalid when any structural change is done to the EMPLOYEES table. 

B

 If the function execution results in an unhandled exception，the exception result is also stored in the cache.

C

 Each time the function is invoked in a different session，the current result in the result cache gets overwritten.

D

 If the function is invoked with a different parameter value，the existing result in the result cache gets overwritten by the latest value.

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相似问题和答案

第1题：

Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? ()

A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


参考答案：C, D, E

第2题：

Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement? （）

  • A、SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);
  • B、SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;
  • C、SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;
  • D、SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);

正确答案:C

第3题：

Examine the description of the EMPLOYEES table:EMP_ID NUMBER(4) NOT NULLLAST_NAME VARCHAR2(30) NOT NULLFIRST_NAME VARCHAR2(30)DEPT_ID NUMBER(2)JOB_CAT VARCHARD2(30)SALARY NUMBER(8,2)Which statement shows the maximum salary paid in each job category of each department? （）

A. SELECT dept_id, job_cat, MAX(salary) FROM employees WHERE salary > MAX (salary);

B. SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id,job_cat;

C. SELECT dept_id, job_cat, MAX(salary) FROM employees;

D. SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id;

E. SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept _ id job _ cat salary;


参考答案：B

第4题：

Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement?（）

  • A、SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);
  • B、SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;
  • C、SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;
  • D、SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);

正确答案:C

第5题：

Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?（）

  • A、SELECT COUNT(*) FROM employees WHERE last_name='Smith';
  • B、SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';
  • C、SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';
  • D、SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';
  • E、SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';

正确答案:D

第6题：

Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? ()

A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);

B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);

C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);

D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);

E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);

F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));


参考答案：C, D, E

第7题：

Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHAR2(30) SALARY NUMBER(8,2) Which statement shows the department ID, minimum salary, and maximum salary paid in that department, only of the minimum salary is less then 5000 and the maximum salary is more than 15000?（）

  • A、SELECT dept_id, MIN(salary(, MAX(salary) FROM employees WHERE MIN(salary) <5000 AND MAX (salary) > 15000;
  • B、SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) < 5000 AND MAX(salary) > 15000 GROUP BY dept_id;
  • C、SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN(salary) <5000 AND MAX (salary) > 15000;
  • D、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id HAVING MIN (salary) < 5000 AND MAX(salary)
  • E、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id, salary HAVING MIN (salary) <5000 AND MAX (salary) > 15000;

正确答案:D

第8题：

Examine the data in the EMPLOYEES table:Which three subqueries work? ()

A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


参考答案：C, D, E

第9题：

Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view? （）

  • A、SELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary < b.maxsal;
  • B、SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))
  • C、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);
  • D、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

正确答案:A

第10题：

Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）

  • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
  • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
  • C、SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
  • D、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
  • E、SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
  • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

正确答案:C,D,E

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