1z0-851
单选题Given classes defined in two different files:What is required at line 5 in class SomeApp to use the process method of BitUtils?（）Aprocess(bytes);BBitUtils.process(bytes);Cutil.BitUtils.process(bytes);DSomeApp cannot use methods in BitUtils.Eimport util
题目
process(bytes);
BitUtils.process(bytes);
util.BitUtils.process(bytes);
SomeApp cannot use methods in BitUtils.
import util.BitUtils.*; process(bytes);
相似问题和答案
第1题：
Givenclassesdefinedintwodifferentfiles：1.packageutil；2.publicclassBitUtils{3.publicstaticvoidprocess（byte[]）{/*morecodehere*/}4.}1.packageapp；2.publicclassSomeApp{3.publicstaticvoidmain（String[]args）{4.byte[]bytes=newbyte[256]；5.//insertcodehere6.}7.}Whatisrequiredatline5inclassSomeApptousetheprocessmethodofBitUtils？（）
A.process（bytes）；
B.BitUtils.process（bytes）；
C.util.BitUtils.process（bytes）；
D.SomeAppcannotusemethodsinBitUtils.
E.importutil.BitUtils.*；process（bytes）；
第2题：
A. the K1 SONET byte； the K2 SONET byte
B. the K2 SONET byte；the K1 SONET byte
C. transmitter switching；receiver detection
D. Line Overhead bytes；Path Overhead bytes
E. Path Overhead bytes；Line Overhead bytes
第3题：
You are writing a method to compress an array of bytes.The array is passed to the method in a parameter named document.You need to compress the incoming array of bytes and return the result as an array of bytes.Which code segment should you use?（）
A.
B.
C.
D.
第4题：
What are disadvantages of Network Address Translation Transparency?（）
- A、There is no disadvantage.
- B、It will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).
- C、It will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).
- D、It will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.
正确答案:B,D
第5题：
A.Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.
B.Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.
C.Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.
D.Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.
E.Themaximumframesizethatcantraversethisinterfaceis1500bytes.
第6题：
A.process(bytes);
B.BitUtils.process(bytes);
C.app.BitUtils.process(bytes);
D.util.BitUtils.process(bytes);
E.import util.BitUtils.*; process(bytes);
F.SomeApp cannot use the process method in BitUtils.
第7题：
Users of a site-to-site VPN are reporting performance problems. The VPN connection employs IPSec and GRE and traverses several Ethernet segments. The VPN packets are being fragmented as they traverse the links. What would be two methods to overcome this problem?（）
A. Employ path MTU discovery.
B. Set the MTU higher than 1500 bytes.
C. Turn off pre-fragmentation for IPSec.
D. Set the MTU value to 1400 bytes.
第8题：
Given classes defined in two different files：1.package util；2.public class BitUtils{3.private static void process（byte[]b）{}4.}1.package app；2.public class SomeApp{3.public static void main（String[]args）{4.byte[]bytes=newbyte[256]；5.//insert code here6.}7.}What is required at line 5 in class SomeApp to use the process method of BitUtils？（）
A.process（bytes）；
B.BitUtils.process（bytes）；
C.app.BitUtils.process（bytes）；
D.util.BitUtils.process（bytes）；
E.importutil.BitUtils.*；process（bytes）；
F.SomeApp cannot use the process method in BitUtils.
第9题：
Users of a site-to-site VPN are reporting performance problems. The VPN connection employsIPSec and GRE and traverses several Ethernet segments. The VPN packets are being fragmented as they traverse the links. What would be two methods to overcome this problem？（）
- A、 Employ path MTU discovery.
- B、 Set the MTU higher than 1500 bytes.
- C、 Turn off pre-fragmentation for IPSec.
- D、 Set the MTU value to 1400 bytes.
正确答案:A,D
第10题：
UPSR protection switching is initiated by （）, while BLSR is initiated by （）.
- A、the K1 SONET byte； the K2 SONET byte
- B、the K2 SONET byte；the K1 SONET byte
- C、transmitter switching；receiver detection
- D、Line Overhead bytes；Path Overhead bytes
- E、Path Overhead bytes；Line Overhead bytes
正确答案:E