西北工业大学

You ______________________ put the passport in the suitcase, I may need it at any time.A、mustn't haveB、wouldn't haveC、shouldn't haveD、won't have

题目
You ______________________ put the passport in the suitcase, I may need it at any time.

A、mustn't have

B、wouldn't have

C、shouldn't have

D、won't have

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相似问题和答案

第1题：

You can stay here tonight.We can ( )you ______in the spare room.

A.put...up

B.put...away

C.put...down

D.put...off


参考答案：A

第2题：

You ( ) walk for miles and miles among the hills without meeting anyone.

A、should

B、need

C、must

D、may


参考答案：D

第3题：

Your little girl is becoming very rude. You ________ scold her.

A.may

B.can

C.ought to

D.need


参考答案：C

第4题：

36． We ___________ keep the new traffic law and learn how to protect ourselves．

A．may．

B．should

C．can

D．need


正确答案：B
36．B【解析】句意：我们应该遵守新的交通法规并学会保护自己。所填词意思为“应该”，表示一种义务和责任，用should。

第5题：

3．—__________ 1 go out for a while?

—No，you __________ You must finish your homework first．

A． Must，needn't

B． Can，may

C． May，mustn't

D． May，must


正确答案：C

第6题：

You needn't go back to London tonight.We can( )you______for the night.

A.put...away

B.put ...up

C.put...off

D.put...down


参考答案：B

第7题：

Our tradition ______ be different _____ yours.

A、can;with

B、must;with

C、need;as

D、may;from


正确答案:D

第8题：

May I take this book out of the reading room? No,you . You read it in here. ( )

A. mightn’t

B. won’t

C. need’t

D. mustn’t


正确答案：D

第9题：

---I haven’t got the reference book yet, but I’ll have a test on the subject next month.

---Don’t worry. You______ have it by Friday.

A. could

B. shall

C. must

D. may


正确答案：B

第10题：

下面的代码用于输出字符数组ch中每个字符出现的次数，应该填入的代码是（）public static void main（String[] args) { char[] ch = { 'a', 'c', 'a', 'b', 'c', 'b' }; HashMap map = new HashMap（); for （int i = 0; i ＜ ch.length; i++) { ＜ 填入代码 ＞ } System.out.println（map); }

A．if (map.contains(ch[i])) { map.put(ch[i], map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }

B．if (map.contains(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }

C．if (map.containsKey(ch[i])) { map.put(ch[i], (int) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }

D．if (map.containsKey(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }


if (map.containsKey(ch[i])) { map.put(ch[i], (Integer)map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }

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