重庆大学

()tonight, why not drop in and play chess with me?A.Since you are freeB.For you are freeC.Because you are freeD.If you would be free

题目

()tonight, why not drop in and play chess with me?

A.Since you are free

B.For you are free

C.Because you are free

D.If you would be free

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相似问题和答案

第1题:

You ( ) me, because I never said I liked coffee without milk.

A、must misunderstand

B、must have misunderstood

C、must be misunderstanding

D、had to misunderstand


参考答案:B

第2题:

You’re such a hardworking student, you()the praise.

A、reserve

B、deserve

C、conserve

D、preserve


正确答案:B

第3题:

Tom: You are playing guitar well. Can you read music? Charles: No, I don't. I just listen to songs on the radio and then play them until they sound right. Tom: ______ Charles: No, really.

A.You're lying

B.You're cheating

C.You are boasting

D.You're kidding


正确答案:D
解析:Tom对Charles不识乐谱也能弹得一手好吉他感到难以置信,这种情况下一般说 You're kidding或You're joking,意思是:“你在开玩笑吧!”或“这不是真的!”。其他几个选项分别表示“撒谎”、“吹嘘”、“欺骗”,都不恰当。

第4题:

me是一个包含3个成员属性为a的集合,you是一个包含2个成员属性为b的集合,则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是

A.ps(me,you):c;

B.ps(you,me):c;

C.ps(a,b):c;

D.ps(b,a):c;


ps(you,me):c;

第5题:

49.—What about some drinks?

—__________.

A. Help, yourself

B. Good idea

C. You're welcome

D. Me,too


正确答案:B
49.B【解析】句意t——来些饮料怎么样?——好主意。选项A的意思是“自用/随便吃”;选项D的意思“我也是”,两个选项均不符合题意;选项C是用来回答 Thank you的问题,故也排除。

第6题:

Does modern logistics mean transportation and delivery?

()Modern logistics is more about effective and efficient flow of materials and information.

A、 Yes, you’re right

B、 No, it’s not the whole story

C、 No, you' re wrong


参考答案:C

第7题:

– David, you've been losing your temper over nothing lately.– ( ).

A. I haven’t been getting much sleep either

B. You’d better not push yourself too hard, or you’ll get sick

C. I’m sorry. I shouldn’t have blown up like that

D. You’d better do exercises regularly


正确答案:C

第8题:

下列程序执行后的输出结果是 included main( ) { char arr[2][4]; strcpy(arr,"you")

下列程序执行后的输出结果是

#included<string.h>

main( )

{ char arr[2][4];

strcpy(arr,"you");strepy(arr[1],"me");

arr[0][3]='&';

cout<<arr<<endl;

}

A.you&me

B.you

C.me

D.err


正确答案:A
解析:本题考察二维数组的标识方式。arr作为数组名单独使用时表示一个指向数组首部的指针,故you放在数组第一行的前三列art[0][0]、arr[0][1]、arr[0][2]中。art[1]表示指向第二行的指针,因此me放在数组第二行的前两列arr[1][0]、arr[1][1]中。而&则直接按照两维下标放到第一行的第四列中。那么输出的时候默认按照从左到右,先上后下的顺序。因此本题的正确答案为A。

第9题:

Me,you是两个初始集合,则下列关于派生集合定义方式正确的是

A.link/me,you/:a;

B.link(me,you):a;

C.link/me you/a;

D.link(me,you)/a;


link(me,you):a;

第10题:

你最好控制一下上网聊天的时间。(汉译英)

A.You'd better set a limit for your online chat time.

B.You'd better set a limit on your online chat time.

C.You'd better set a limit on your online chatting time.

D.You'd better set a limit for your online chatting time.


You'd better set a limit on your online chatting time.