Customers also find access slow, so I'm getting it () up.
A、speeded
B、speed
C、speeding
第1题:
第2题:
A.interfaceEthernet0/0 I.pv6traffic-filterNoULAout I.pv6access-listNoULA Denyipv6FC00::/8any Permitipv6anyany
B.interfaceEthernet0/0 I.pv6traffic-filterNoULAout I.pv6access-listNoULA Denyipv6FC00::/7anyP ermitipv8anyany
C.interfaceEthernet0/0 I.pv6access-groupNoULAout I.pv6access-listNoULA Denyipv6FC00::/8anyP ermitipv6anyany
D.interfaceEthernet0/0 I.pv6access-groupNoULAout I.pv6access-listNoULA Denyipv6FC00::/7any Permitipv6anyany
第3题:
Access中用于执行指定的SO.L语言的宏操作名是( )。
第4题:
有如下程序段#include "stdio.h"#include "string.h"#define N 10#define M 10char *find(char(*a)[M],int n){ char *q;int i; q=a[0]; for(i=0;i<n;i++) if(strcmp(a[i],q)<0)q=a[i]; return q;}main(){ char s[N][M]={"tomeetme","you","and","he","china"}; char *p; int n=5; p=find(s,n); puts(p);}则执行后输出的结果为A.he B.and C.you D.tomeetme
第5题:
阅读以下说明,回答问题1~4,将解答填入对应的解答栏内。
[说明] 假设二叉树采用连接存储结构进行存储,root 指向根接点,p 所指结点为任一给定的结点,编写一个求从根结点到p所指结点之间路径的函数。
void path (root, p)
btree * root, * p;
{
Btree *stack[m0], *s;
int tag[m0], top =0, i, find =0;
s =root;
do
{
while (s ! = NULL)
{
stack [top] = s;
tag[top] =0;
((1))
}
if (top >0)
{
((2))
if (tag[top] = =1)
{
if((3))
{
for (i=1; i< =top; i+ + printf ("%d" ,stack[i]- >data);
find=1;
}
else top - -;
}
if((4))
{
p=p- >right;
((5))
}
}
} while (find || (s! = NULL && top ! =0));
}
第6题:
A、chain
B、chaining
C、chained
D、to chain
第7题:
Come on through. I'm sorry your wife couldn't() it.
A、come
B、make
C、meet
D、find
第8题:
We have stayed at Shanghai port for a long timeThe fouling on the ship’s hull greatly increases her _____.
A.power
B.speed
C.resistance
D.thrust force
第9题:
(A) also
(B) so
(C) /
(D) hence
正确答案:B
解答参考:B在肯定句中,当表示前面所说的情况也适用于另一人的时候,后面的句子用so引导,主谓倒装。【译文】我很愿意帮忙,其他人也都很愿意