广东开放大学
The only games( )I play are football and tennis.A.whoB.whichC.whatD.when
题目
A.who
B.which
C.what
D.when
相似问题和答案
第1题：
I _________ table tennis quite well, but I haven ’t had time to play since the New Year.
A. will play
B. have played
C. play
第2题：
A、will play
B、have palyed
C、played
D、play
第3题：
I_____ jogging every morning in the park.
A. go
B. do
C. play
第4题：
put computers to practical business use, but below the surface it is the heart of an(22) - the kernel - that provides the technical wizardry to juggle multiple programs, connect to networks and store(23).A traditional kernel provides all the functions for applications. The kernel(24) memory, I/O devices and parcels out processor time.The kernel also supports(25) and fault tolerance, which is the ability to recover automatically when parts of the system fail.
A．Databases
B．Applications
C．Drivers
D．Games
第5题：
The following statements have been made about life cycle costing:
(i) It focuses on the short-term by identifying costs at the beginning of a product’s life cycle
(ii) It identifies all costs which arise in relation to the product each year and then calculates the product’s profitability on an annual basis
(iii) It accumulates a product’s costs over its whole life time and works out the overall profitability of a product
(iv) It allocates costs to each stage of a product’s life cycle and writes them off at the end of each stage
Which of the above statements is/are correct?
A.(i) and (iii)
B.(iii) only
C.(i) and (iv)
D.(ii) only
All of the statements are false except statement (iii).
第6题：
I've always enjoyed_____ football.
A. to play
B. playing
C. play
第7题：
根据下列程序的执行结果，可以断定划线部分的修饰符应为______。执行结果：
i9a football is created.
a football is created.
i=10
a football is destroyed.
a football is created.
i=20
a football is destroyed.
a football is destroyed.
源程序：
include＜iostream.h＞
class Football
{
public:
Football( ){cout＜＜"a football is created."＜＜endl;}
～Football( ){tout＜＜"a football is destroyed."＜＜endl;}
};
void func(int i)
{
______Football f1;
Football f2;
cout＜＜"i="＜＜i＜＜endl;
}
void main( )
{
func(10);
func(20);
}
static 解析：观察一下输出中对象的构造函数和析构函数的执行次数可以看出，再次进入时某对象没有被构造，亦即该对象在func执行后没有被销毁，再次进入时则不需要重构，可以体现这种功能的标识符只有static。
第8题：
After they finished _____football,they went for a drink in a pub.
A.playing
B.to play
C.play
第9题：
The following information is available for a manufacturing company which produces multiple products:
(i) The product mix ratio
(ii) Contribution to sales ratio for each product
(iii) General fixed costs
(iv) Method of apportioning general fixed costs
Which of the above are required in order to calculate the break-even sales revenue for the company?
A.All of the above
B.(i), (ii) and (iii) only
C.(i), (iii) and (iv) only
D.(ii) and (iii) only
The method of apportioning general fixed costs is not required to calculate the break-even sales revenue.
第10题：
[说明]
对部分乐器进行建模，其类图如下图所示，包括：乐器(Instrument)、管乐器(Wind)、打击乐器(Percussion)、弦乐器(Stringed)、木管乐器(Woodwind)、铜管乐器(Brass)。
类图
下面是实现上述设计的C++代码，其中音乐类(Music)使用各类乐器(Instrument)进行演奏和调音等操作。
using namespace std; enum Note(/*枚举各种音调*/ MIDDLE_C,C_SHARP,B_FLAT }; classInstrument{/*抽象基类,乐器*/ public: ______; //play函数接口 virtual voidadjust()=0; //adjust函数接口 }; class Wind ______{ public: void play(Note n) { cout＜＜"Wind.play() "＜＜n＜＜endl; } void adjust(){cout＜＜"Wind.adjust()"＜＜endl; } ); /*类Percussion和Stringed实现代码略*/ class Brass ______{ public: void play(Note n) {cout＜＜"Brass.play() "＜＜n＜＜endl; } void adjUSt(){cout＜＜"Brass.adjust()"＜＜endl;) }; classWoodwind:public Wind{ public: void play(Note n) { cout＜＜"Woodwind.play()"＜＜n＜＜endl; } }; class MusiC { public: voidtune(Instrument*i) { i-＞play(MIDDLE_C.; } voidadjust(Instrument*i){ i-＞adjust(); } void tuneAll(______ e[],int numIns){ /*为每个乐器定调*/ for(int i=0; i＜numIns; i++){ this-＞tune(e[i]); this-＞adjust(e[i]); } } }; /*使用模板定义一个函数size,该函数将返回数组array的元素个数,实现代码略*/ int main(){ Music*music=______ Music(); Instrument*orchestra[]={new Wind(),new Woodwind() }; music-＞tuneAll(orchestra,size(orchestra));/*size返回数组orchestra的元素个数*/ for(int i=0;i＜size(orchestra);i++) deleteorchestra[i]; delete music; }
本程序运行后的输出结果为：
Wind.play()0 Wind.adjust() Woodwind.play()0 Wind.adjust()
:public Instrument
:public Wind
Instrument*
new