已知反应CaCO3（s）═══CaO（s）+CO2（g）。增大系统总压，平衡向着什么方向移动？（）A、正反应方向B、逆反应方向C、不移动D、反应停止

A、Sub plus(sum, a , b ): sum = a + b: End Sub

B、Sub plus(ByVal sum , a , b ): sum = a + b: End Sub

C、Sub plus(sum , ByVal a, ByVal b ): sum = a + b: End Sub

D、Sub plus(sum , ByRef a , ByRef b ): sum = a + b: End Sub

以下程序用于求S=1+3+32+33+…+310的值。

Private Sub Commandl_Click()

S=1

T=1

ForI=1 To 10

T=______

S=S+T

NextI

Print"S="；S

End Sub

化学反应 CaCO3(s)=CaO(s)+CO2(g)的()

A△H>0，△S>0

B△H>0，△S<0

C△H<0，△S>0

D△H<0，△S<0

下列程序运行后的输出结果是______。Private Sub f(k,s) s = 1 for j = 1 To k s=s*j Next jEnd SubPrivate Sub Command1_ Click () Sum = 0 for i = 1 To 3 Call f(i, s) Sum = Sum + s Next i Print Sum End Sub

A．0

B．3

C．6

D．9

写出程序运行的结果

Public class Base

Public virtual string Hello() {return “Base”;}

Public class Sub:Base

Public override string Hello() {return “Sub”;}

1. Base b = new Base(); b.Hello;

2. Sub s = new Sub(); s.Hello;

3. Base b = new Sub (); b.Hello;

4. Sub s = new Base(); s.Hello;

反应CaCO3(s)=CaO(s)+CO2(g)的标准平衡常数的说法正确的是。

A、等于CO2(g)的分压

B、等于CO2(g)的相对分压

C、与CaCO3、CaO和CO2有关

D、无法确定

编写如下事件过程： Private sub sub1 (ByVal x1 As String, y1 As String) Dim xt As String Dim i As Integer i = Len(x1) Do While i＞= 1 xt = xt + Mid(x1, i, 1) i=i-1 Loop y1 = xt End Sub Private Sub Form. Click() Dim s1 As String, s2 As String s1= "teacher" sub1 s1, s2 Print s2 End Sub 程序运行后，单击窗体，则窗体上显示的内容是

A．rehcaet

B．tahreee

C．themee

D．eerthea

A、Sub S1(ByVal n!())

B、Sub S1(n!) as Integer

C、 Function S1%(S1%)

D、 Function S1(ByVal n!)

下面程序的输出结果是。 Private Sub Commandl_Click ch$=“ABCDEF” proc ch：Print ch End Sub Private Sub proc(ch As Stnng) s=“” For k=Len(ch) TO 1 Step -1 s=s&Mid(ch，k，1) Next k ch=s End Sub A．ABCDEF B．FEDCBA C．A D．F

下列程序运行后的输出结果是______。

Private Sub f(k，s)

s=1

For j=1 To k

s=s*j

Next

End Sub

Private Sub Command1_Click()

Sum=0

For i=1 To 3

Call f(i，s)

Sum=Sum+s

Next

Print Sum

End Sub