CMS专题

单选题Given the following statements: CREATE TABLE tab1 (col1 INT); CREATE TABLE tab2 (col1 INT); CREATE TRIGGER trig1 AFTER UPDATE ON tab1 REFERENCING NEW AS new1 FOR EACH ROW MODE DB2SQL INSERT INTO tab2 VALUES(new1.col1); INSERT INTO tab1 VALUES(2),(3); W

题目
单选题
Given the following statements: CREATE TABLE tab1 (col1 INT); CREATE TABLE tab2 (col1 INT); CREATE TRIGGER trig1 AFTER UPDATE ON tab1 REFERENCING NEW AS new1 FOR EACH ROW MODE DB2SQL INSERT INTO tab2 VALUES(new1.col1); INSERT INTO tab1 VALUES(2),(3); What is the result of the following query? SELECT count(*) FROM tab2;()
A

3

B

2

C

1

D

0

参考答案和解析
正确答案: D
解析: 暂无解析
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相似问题和答案

第1题:

Given the following DDL and INSERT statements:CREATE VIEW v1 AS SELECT col1 FROM t1 WHERE col1 > 10; CREATE VIEW v2 AS SELECT col1 FROM v1 WITH CASCADED CHECK OPTION; CREATE VIEW v3 AS SELECT col1 FROM v2 WHERE col1 < 100; INSERT INTO v1 VALUES(5); INSERT INTO v2 VALUES(5); INSERT INTO v3 VALUES(20); INSERT INTO v3 VALUES(100);How many of these INSERT statements will be successful?()

A.0

B.1

C.2

D.3


参考答案:C

第2题:

The following statements:CREATE TABLE t1 (col1 INT NOT NULL, PRIMARY KEY(col1)); CREATE TABLE t2 (col1 INT NOT NULL, col2 CHAR(1) NOT NULL, PRIMARY KEY (col1, col2), FOREIGN KEY (col1) REFERENCES t1 (col1) ON DELETE CASCADE ON UPDATE RESTRICT); CREATE TABLE t3 (col1 INT NOT NULL, col2 INT NOT NULL, PRIMARY KEY (col1, col2),FOREIGN KEY (col1) REFERENCES t1 (col1) ON DELETE NO ACTION ON UPDATE RESTRICT);INSERT INTO t1 VALUES (1), (2); INSERT INTO t2 VALUES (1, ‘a‘), (1, ‘b‘), (2,‘c‘); INSERT INTO t3 VALUES (1, 100), (2, 200), (2,300);How many rows will be deleted by the following DELETE statement? DELETE FROM t1 WHERE col1= 1;()

A.4

B.3

C.1

D.0


参考答案:D

第3题:

An application needs a table for each connection that tracks the ID and Name of all items previously ordered and committed within the connection. The table also needs to be cleaned up and automatically removed each time a connection is ended. Assuming the ITEMS table was created with the following SQL statement:CREATE TABLE items item_no INT, item_name CHAR(5), item_qty INT)Which of the following SQL statements will provide the table definition that meets the specified requirements?()

A.DECLARE GLOBAL TEMPORARY TABLE tracker AS (SELECT item_no, item_name FROM items) WITH NO DATA ON COMMIT PRESERVE ROWS ON DISCONNECT DROP TABLE

B.DECLARE GLOBAL TEMPORARY TABLE tracker AS (SELECT item_no, item_name FROM items) WITH NO DATA ON COMMIT PRESERVE ROWS

C.CREATE TABLE systmp.tracker AS (SELECT item_num, item_name FROM items) WITH NO DATA ON COMMIT PRESERVE ROWS

D.CREATE TABLE tracker AS (SELECT item_num, item_name FROM items) ON COMMIT PRESERVE ROWS ON DISCONNECT DROP TABLE


参考答案:B

第4题:

Table TAB1 was created using the following statement: CREATE TABLE tab1 (c1 INT, c2 INT, c3 INT, c4 INT, c5 INT); If column C1 is unique and queries typically access columns C1, C2 and C3 together, which statement(s) will createindex(es) that will provide optimal query performance?()

  • A、CREATE UNIQUE INDEX xtab1 ON tab1 (c1); CREATE INDEX xtab2 ON tab1 (c2) INCLUDE (c3)  
  • B、CREATE UNIQUE INDEX xtab1 ON tab1 (c1) INCLUDE (c2, c3) 
  • C、CREATE UNIQUE INDEX xtab1 ON tab1 (c3, c2, c1)  
  • D、CREATE UNIQUE INDEX xtab1 ON tab1 (c2) INCLUDE (c1, c3)

正确答案:B

第5题:

Given the following DDL for the PARTS table:CREATE TABLE parts (part_no INT(9) NOT NULL, part_name VARCHAR(24), part_remain INT(9));All part numbers entered will be different and all rows should be displayed in order of increasing part numbers whenever the table is queried. Which of the following create index statements will meet this criteria and require the least amount of storage for the index object?()

A.CREATE UNIQUE INDEX idx_partno ON parts(part_no)

B.CREATE UNIQUE INDEX idx_partno ON parts(part_name ASC)

C.CREATE UNIQUE INDEX idx_partno ON parts(part_name, part_no ASC)

D.CREATE UNIQUE INDEX idx_partno ON parts(part_no, part_name ASC)


参考答案:A

第6题:

Given the following statements:CREATE TABLE tab1 (col1 INT); CREATE TABLE tab2 (col1 INT); CREATE TRIGGER trig1 AFTER UPDATE ON tab1 REFERENCING NEW AS new1 FOR EACH ROW MODE DB2SQL INSERT INTO tab2 VALUES(new1.col1); INSERT INTO tab1 VALUES(2),(3);What is the result of the following query? SELECT count(*) FROM tab2;()

A.3

B.2

C.1

D.0


参考答案:D

第7题:

Given the following requirements:Create a table named TESTTAB, which has an identity column named ACTIVITYNO. Define the identity column to generate the values for the column by default. Start the values at 10 and increment by 10. Make the identity column unique. Which of the following CREATE statements will successfully create this table?()

A.CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 10 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))

B.CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTNO))

C.CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY (START WITH 10 INCREMENT BY 1), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))

D.CREATE TABLE TESTTAB (ACTIVITYNO SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY (START WITH 10 INCREMENT BY 10), ACTKWD CHAR(6) NOT NULL, ACTDESC VARCHAR(20) NOT NULL, UNIQUE(ACTIVITYNO))


参考答案:D

第8题:

Which of the following statements is used to grant user TOM and Application team APPGRP the ability to add data to table TAB1?()

A.GRANT ADD DATA ON TABLE tab1 TO GROUP tom appgrp

B.GRANT INSERT TO USER tom, GROUP appgrp ON TABLE tab1

C.GRANT INSERT ON TABLE tab1 TO USER tom, GROUP appgrp

D.GRANT ADD DATA ON TABLE tab1 TO USER appgrp, GROUP tom


参考答案:C

第9题:

你定义了一个对象类型myOBJ,要基于该类型来创建表tab1,语句为()。

A.CREATE TABLE tab1 OF myOBJ

B.CREATE TABLE myOBJ OF tab1

C.CREATE TABLE tab1 AS myOBJ

D.CREATE TABLE tab1 TYPE OF myOBJ


参考答案:C

第10题:

If a unique constraint is defined on column COL1 of table TAB1, what are the characteristics of COL1?()

  • A、COL1 will accept NULL values and can be referenced in another table's foreign key specification.
  • B、COL1 will not accept NULL values and cannot be referenced in another tables foreign key specification.
  • C、COL1 will not accept NULL values and can be referenced in another tables foreign key specification.
  • D、COL1 will accept NULL values and cannot be referenced in another tables foreign key specification.

正确答案:C

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