1z0-851

单选题Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()Aprocess(bytes);BBitUtils.process(bytes);Capp.BitUtils.process(bytes);Dutil.BitUtils.process(bytes);Eimport util.BitUtils

题目
单选题
Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()
A

process(bytes);

B

BitUtils.process(bytes);

C

app.BitUtils.process(bytes);

D

util.BitUtils.process(bytes);

E

import util.BitUtils.*; process(bytes);

F

SomeApp cannot use the process method in BitUtils.

参考答案和解析
正确答案: A
解析: 暂无解析
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相似问题和答案

第1题:

Givenclassesdefinedintwodifferentfiles:1.packageutil;2.publicclassBitUtils{3.publicstaticvoidprocess(byte[]){/*morecodehere*/}4.}1.packageapp;2.publicclassSomeApp{3.publicstaticvoidmain(String[]args){4.byte[]bytes=newbyte[256];5.//insertcodehere6.}7.}Whatisrequiredatline5inclassSomeApptousetheprocessmethodofBitUtils?()

A.process(bytes);

B.BitUtils.process(bytes);

C.util.BitUtils.process(bytes);

D.SomeAppcannotusemethodsinBitUtils.

E.importutil.BitUtils.*;process(bytes);


参考答案:C

第2题:

UPSR protection switching is initiated by (), while BLSR is initiated by ().

A. the K1 SONET byte; the K2 SONET byte

B. the K2 SONET byte;the K1 SONET byte

C. transmitter switching;receiver detection

D. Line Overhead bytes;Path Overhead bytes

E. Path Overhead bytes;Line Overhead bytes


参考答案:E

第3题:

You are writing a method to compress an array of bytes.The array is passed to the method in a parameter named document.You need to compress the incoming array of bytes and return the result as an array of bytes.Which code segment should you use?()

A.

B.

C.

D.


参考答案:C

第4题:

Which two statements are true when the extended system ID feature is enabled? ()

  • A、The BID is made up of the bridge priority value(two bytes) and bridge MAC address (six bytes).
  • B、The BID is made up of the bridge priority (four bits), the system ID (12 bits), and a bridge MAC address (48 bits).
  • C、The BID is made up of the system ID (six bytes) and bridge priority value (two bytes).
  • D、The system ID value is the VLAN ID (VID).
  • E、The system ID value is a unique MAC address allocated from a pool of MAC addresses assigned to the switch or module.
  • F、The system ID value is a hex number used to measure the preference of a bridge in the spanning-tree algorithm.

正确答案:B,D

第5题:

WhichofthefollowingistrueabouttheMPLSheaderanditsEXPfieldsize?()

A.TheMPLSheaderis2bytes,andtheEXPfieldis3bitslong.

B.TheMPLSheaderis1byte,andtheEXPfieldis3bitslong.

C.TheMPLSheaderis4bytes,andtheEXPfieldis3bitslong.

D.TheMPLSheaderis3bytes,andtheEXPfieldis3bitslong.


参考答案:C

第6题:

Given classes defined in two different files:What is required at line 5 in class SomeApp to use the process method of BitUtils?()

A.process(bytes);

B.BitUtils.process(bytes);

C.app.BitUtils.process(bytes);

D.util.BitUtils.process(bytes);

E.import util.BitUtils.*; process(bytes);

F.SomeApp cannot use the process method in BitUtils.


参考答案:F

第7题:

Usersofasite-to-siteVPNarereportingperformanceproblems.TheVPNconnectionemploysIPSecandGREandtraversesseveralEthernetsegments.TheVPNpacketsarebeing fragmentedastheytraversethelinks.Whatwouldbetwomethodstoovercomethisproblem?()

A.EmploypathMTUdiscovery.

B.SettheMTUhigherthan1500bytes.

C.Turnoffpre-fragmentationforIPSec.

D.SettheMTUvalueto1400bytes.


参考答案:A, D

第8题:

Given classes defined in two different files:1.package util;2.public class BitUtils{3.private static void process(byte[]b){}4.}1.package app;2.public class SomeApp{3.public static void main(String[]args){4.byte[]bytes=newbyte[256];5.//insert code here6.}7.}What is required at line 5 in class SomeApp to use the process method of BitUtils?()

A.process(bytes);

B.BitUtils.process(bytes);

C.app.BitUtils.process(bytes);

D.util.BitUtils.process(bytes);

E.importutil.BitUtils.*;process(bytes);

F.SomeApp cannot use the process method in BitUtils.


参考答案:F

第9题:

Refer to the exhibit. What is the meaning of the output MTU 1500 bytes?()

A.Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.

B.Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.

C.Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.

D.Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.

E.Themaximumframesizethatcantraversethisinterfaceis1500bytes.


参考答案:D

第10题:

What are disadvantages of Network Address Translation Transparency?()

  • A、There is no disadvantage.
  • B、It will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).
  • C、It will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).
  • D、It will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.

正确答案:B,D

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